TUGAS PERTEMUAN 2

Hitunglah jumlah Network dan Host yang akan terbentuk dari alamat IP Address dibawah ini, kemudian buat rincian alamat (Network, Broadcast) beserta alamat yang dapat diberikan kepada setiap host (minimal untuk 5 host/komputer): 

1. 192.168.10.1/30 

2. 172.168.10.1/16 

3. 172.168.10./22 

4. 10.168.5.1/8 

5. 10.168.5.1/17

JAWABAN:

Nomor 1:

Netmask = 255.255.255.252

In binary = 11111111. 11111111. 11111111.11111100

Used to calculate = 11111100

Network = 2^n

= 2^6

= 64 Network

Host = 2^h-2

     = 2^2-2

     = 2 Host

Nomor 2 :

Netmask = 255.255.0.0

In Binary = 11111111.11111111.00000000.00000000

Used to calculate = 00000000.00000000

Network = 2^n

        = 2^0

        = 1 Network

Host    = 2^h-2

= 2^16-2

= 65534 Host

Nomor 3 :

Netmask : 255.255.252.0

In Binary : 11111111.11111111.11111100.00000000

Used to calculate = 11111100.00000000

Network = 2^n

        = 2^6

        = 64 Network

Host    = 2^h-2

= 2^10-2

= 1022 Host

Nomor 4 :

Netmask   : 255.0.0.0 

In Binary : 11111111.00000000.00000000.00000000

Used to calculate = 00000000.00000000.00000000

Network = 2^n

        = 2^0

        = 1 Network

Host    = 2^h-2

= 2^24-2

= 167772614 Host

Nomor 5 :

Netmask : 255.255.128.0

In Binary : 11111111.11111111.10000000.00000000

Used to calculate = 11111111.10000000.00000000

Network = 2^n

        = 2^9

        = 512 Network

Host    = 2^h-2

= 2^15-2

= 32766 Host